C++怎样把2014-12-19 10:25转换成1418955940的格式

time_t Str2Time(LPCTSTR lpszTime)
{
    ASSERT(NULL != lpszTime);

    struct tm time = {0};
    _stscanf(lpszTime, _T("%4d-%2d-%2d %2d:%2d"), 
        &time.tm_year,
        &time.tm_mon,
        &time.tm_mday,
        &time.tm_hour,
        &time.tm_min);
    time.tm_year -= 1900;
    time.tm_mon -= 1;
    time.tm_isdst = -1;
    time_t Value = mktime(&time);
    return Value;
}

int _tmain(int argc, TCHAR* argv[], TCHAR* envp[])
{
    cout<<Str2Time(_T("2014-12-19 10:25"))<<endl;
    return 0;
}