Gson解析json数据时如果属性值为null则会报空

贴一个google+的答案，将null替换成""

import java.lang.reflect.Type;

public class StringConverter implements JsonSerializer<String>, 
    JsonDeserializer<String> { 
public JsonElement serialize(String src, Type typeOfSrc, 
    JsonSerializationContext context) { 
    if ( src == null ) { 
        return new JsonPrimitive(""); 
    } else { 
        return new JsonPrimitive(src.toString()); 
} 
public String deserialize(JsonElement json, Type typeOfT, 
    JsonDeserializationContext context) 
        throws JsonParseException { 
    return json.getAsJsonPrimitive().getAsString(); 
} 
}

然后这么用：

GsonBuilder gb = new GsonBuilder(); 
gb.registerTypeAdapter(String.class, new StringConverter()); 
Gson gson = gb.create();